400+0.1x^2=0.2x

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Solution for 400+0.1x^2=0.2x equation: 



400+0.1x^2=0.2x

We move all terms to the left:

400+0.1x^2-(0.2x)=0

We add all the numbers together, and all the variables

0.1x^2-(+0.2x)+400=0

We get rid of parentheses

0.1x^2-0.2x+400=0

a = 0.1; b = -0.2; c = +400;
Δ = b2-4ac
Δ = -0.22-4·0.1·400
Δ = -159.96
Delta is less than zero, so there is no solution for the equation

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